Problem 3

0.25 mol of NOCl was initially in a 2.0 L container at 500 șC.  After equilibrium it is found that the concentration of NOCl has dropped to 0.090 mol/L.

2NOCl (g) 2NO (g) + Cl2 (g)

What is K?

1.To solve this problem you should use an IRE table something like the following.

2NOCl (g)

2NO (g) + Cl2 (g)
I     0   0
R  
E   0.090  

2. What is the calculated value for K? 

Remember that you type numbers in scientific notation like 1.234E-05 for 1.234x10-5

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