le Châtelier's Principle: common ion effect

Copper (II) ions react with halide ions (Cl-, Br-, I-) to form complex ions.  While Cu2+ (aq) ions are blue, the resulting product is green.  The following equation can be used to represent this process.

Cu2+ (aq) + 4Cl- (aq) CuCl42- (aq)

We can use le Châtelier's principle to predict what should happen as we change the concentration of the ions in solution.  Adding more Cl- will shift the equilibrium to the right, so the solution will become more green.  One interesting result of this is that the color of copper(II) chloride (CuCl2)solutions depends on concentration: when dilute there is a smaller amount of Cl- so the color is blue.  However, as the concentration increases the solution becomes more of a green-blue color, rather than a true blue.

There are other ways to change the concentration of Cl- ions without dissolving more CuCl2

If water was evaporated, then we would expect (from le Châtelier's principle):
the color to become more blue
the color to become more green
no change in the color of the solution

The last method, adding the same ion from a different source is called adding a "common ion".  This is a standard chemical procedure, and the change predicted by le Châtelier's principle when we mix the same ions from different sources, is called the "common ion effect".  For example, we would have a common ion of Cl- if we dissolved some NaCl in the solution.  We would have a common ion of Cu2+ if we dissolved some Cu(NO3)2 (s) in the solution.

Consider this solution equation.

Cu2+ (aq) + 4Br- (aq) CuBr42- (aq)

Which of the following solids when dissolved would cause the common ion effect in a solution of CuBr2?
Cu2SO4    NaCl KBr
MgBr2 all of them none of them

In this experiment you will examine the common ion effect on a simple solution equilibrium.

Materials:

Procedures:

Caution: Copper (II) chloride is moderately dangerous (harmful if swallowed, causes irritation to skin, eyes and respiratory tract), so be careful not to ingest it, spill on your skin, or get it into your eyes.  If it does come in contact with your skin, wash thoroughly with plenty of water.  The other substances used in this experiment are relatively safe; however, you need to observe the normal safety precautions you would for any lab while using them.  Wear a lab apron and safety goggles at all times.

1. Get about 20 mL (about 1/2 a test tube full) of a 0.5 M solution of CuCl2 in a test tube.
2. Measure onto separate weighing papers 0.5 g, 1.0 g, and 1.5 g of NaCl.  Note: in order to save time while weighing, you can follow this optional method.
3. Measure 1.5 g of NaNO3 onto a fourth weighing paper.
4. Using a calibrated pipet put 4 mL of the CuCl2 solution into each test tube.
5. Leave the first test tube as is.  Add 0.5 g of NaCl to test tube 2.  Add 1.0 g of NaCl to test tube 3.  Add 1.5 g of NaCl to test tube 4.
6. Add 1.5 g of NaNO3 to test tube 5.
7.  Stopper each tube with a rubber stopper, shake, and observe the contents.   Note: it may be hard to get all the solid to dissolve, as you are very near a saturated solution of the solid in the higher mass tubes.

Conclusion:

Observe the color of each tube, and explain the results in terms of le Châtelier's principle.  Click to see a photograph of the results

1.Which test tube has the highest concentration of Cl- ions?
1      2     3     4     5

2. The NaNO3 was added to show that if there is no common ion, then the equilibrium does not change.
True      False

3. The color change in this reaction is not what you would expect from the prediction of le Châtelier's principle.
True      False

4. The procedure did not suggest adding solid CuSO4 to any of the test tubes.  Write out an answer that explains what you would expect to see if you did so.   Then check your answer to see if it is correct.

Optional method of weighing NaCl:  On one piece of weighing paper, measure 3 g of NaCl.  Divide it into 6 equal piles.   Transfer one pile (0.5 g) to one piece of weighing paper.  Transfer two piles (1.0 g) to a second piece of paper.  The remaining three piles (1.5 g) can stay on the original paper.  This saves time if balances are limited.